x^2-9=x-3(x-3+16)

Solution for x^2-9=x-3(x-3+16) equation:

x^2-9=x-3(x-3+16)

We move all terms to the left:

x^2-9-(x-3(x-3+16))=0

We add all the numbers together, and all the variables

x^2-(x-3(x+13))-9=0


We calculate terms in parentheses: -(x-3(x+13)), so:

x-3(x+13)

We multiply parentheses

x-3x-39

We add all the numbers together, and all the variables

-2x-39

Back to the equation:

-(-2x-39)


We get rid of parentheses

x^2+2x+39-9=0

We add all the numbers together, and all the variables

x^2+2x+30=0

a = 1; b = 2; c = +30;
Δ = b2-4ac
Δ = 22-4·1·30
Δ = -116
Delta is less than zero, so there is no solution for the equation